Gold Electron Configuration

Help, what about the electronic configuration of the gold ion (+3)?

Gold is a transitional element. There, electrons get lost not only in their valence, but also in the S below them. When Ao loses three electrons, the first one leaves the ■■■■ 6s1 (Valence S) and the next three leaves 5d10. The order of Au3 + ion is [Xe] 4f14 fd8.

Gold electron configuration

Gold Electron Configuration

Help, what about the electronic configuration of the gold ion (+3)? 3
I know this usually happens.
Au: [Xe] 6s1 4f14 fd10
As ion + 1 would be [Xe] 4f14 5d10
What is the order of electrons if gold has +3 charge? I don't understand where 3 electrons can be extracted from gold.
update
Why do two electrons want to leave the ■■■■ cavity of their cage? I wasn't there when I was being taught Cl, but can someone explain to me why this electron wants two electrons from the third mouth, or just to make sure two electrons come out of the mouth?
Thank you very much!
Gold is a transitional element. There, electrons get lost not only in their valence s but also in the s below them. When Au loses three electrons, the first electron loses 6s1 (valence s) and the next three electrons lose 5d10. The setting of Au3 + ion is [Xe] 4f14 fd8.
* The number in parentheses is the number of electrons for every million degrees of power. He = 1s (2) 2. Li = 1s (2) 2s (one million) 3. Be = 1s (2) 2s (2) 4. B = 1s (2) 2s (2) 2p (one million) 5. C = 1s (2) 2s (2) 2p (2) 6. N = 1s (2) 2s (2) 2p (3) Just! N_n
Just pull it out of Dortel, then 5d8