Power Reducing Formula

Have you used the power reduction formula to rewrite the expression?

6 sins 4x

Yes

(Sin 2x) (because 2x)

I do a lot of work on double angle, subtraction and half angle formulas. I'm crying here because there's not a single problem I can solve! Help :(

update

Why do you change from 4 to 6? I got a little involved in the process.

Anyway, that's not the right answer (from the first book). Any other ideas?

It requires a little knowledge.

6 sin 4x = 6 (sin²x) (sin (x)

sin²x = (1 cos 2x) / 2, then alternate and multiply. You get a term other than sin²x, so use those formulas. It is done there.

Formula reduction formula

Sin 2x = (1kos 2x) / 2

6 sins 4x = (6/4) (1kos 2x) 2 = (3/2) (1 2kos 2x + kos; 2 (2x))

And enter the answer 2 (2x) = (1 + cos4x) / 2 in> answer

Power Reducing Formula

Did you use the power reduction formula to rewrite the expression? ۔
6 sins 4x.
And
(Sin x 2x) (cos 2x)
I do a lot of my work on double angle, structure and half angle formulas. I'm crying here because there's not a single problem I can solve! Help :(
update
Why did you change from 4 to 6? I got a little involved in the process.
Ener, this is not the right answer (from the first book). Any other ideas?
It only requires a little knowledge.
6 sins 4x = 6 (sin²x) (sin²x)
sin²x = (1 cos 2x) / 2, then alternate and multiply. You get a term other than sin²x, so use the formula M. It is done there.
Sin 2 x = (1cos2x) / 2.
6 sins 4x = (6/4) (1cos2x) 2 = (3/2) (1 2cos2x + cos 2 (2x))
Enter cos 2 (2x) = (1 + cos4x) / 2 in the answer.